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Listen to part 4 chem isu by John Doe MP3 song. part 4 chem isu song from John Doe is available on Audio.com. The duration of song is 01:50. This high-quality MP3 track has 288.347 kbps bitrate and was uploaded on 20 Jun 2024. Stream and download part 4 chem isu by John Doe for free on Audio.com – your ultimate destination for MP3 music.
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The Combined Gas Law combines Charles's Law, Gay-Lussac's Law, and Boyle's Law. It relates one thermodynamic variable to another while keeping everything else constant. The formula for this law is constant equals pressure times volume divided by temperature. It can also be expressed as initial pressure times initial volume divided by initial temperature equals final pressure times final volume divided by final temperature. An example is a balloon filled with helium on Earth's surface, which will rise and experience changes in temperature and air pressure. A mathematical example involves calculating the final pressure of gas in a refrigerator given initial and final volumes and temperatures, and initial pressure. By plugging in the values and solving the equation, the final pressure is determined to be around 30.52 atm. The Combined Gas Law. The Combined Gas Law is the law that combines Charles's Law, Gay-Lussac's Law, and Boyle's Law. This combination relates to one thermodynamic variable to another holding everything else constant. The formula for this law can be expressed as constant equals pressure times volume divided by temperature. Or when two variables are compared in two different conditions, it can also be expressed as initial pressure times initial volume divided by initial temperature equals final pressure times final volume divided by final temperature. As for a real life example, one variable can be when a balloon is filled with helium on the surface of Earth. The balloon will have a certain pressure, temperature, and volume. Now if the balloon is let go, it will begin to rise. As it goes further into the air, the temperature and air pressure will also begin to drop. Let's find out for using this law in a mathematical example. In a refrigerator, the initial volume of gas is 5 liters and the final volume is 3 liters. Calculate the final pressure of gas given that the initial temperature is 273 K while the final temperature is 200 K. And the initial pressure is 25 atm. For this problem, you are given five variables. Initial temperature, 25 atm. Initial volume, 5 liters. Final volume, 3 liters. Initial temperature, 273 K. And final temperature, 200 K. And since this problem is comparing two different conditions, you will be using the longer formula. When the numbers are plugged in, it will look like something like 25 times 5 divided by 273 equals final pressure times 3 divided by 200. Now after solving both sides of the equation, you would want to get PF by itself. So you would want to divide 0.457 with 0.015. And after that, your final pressure should be around 30.52 atm.
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